contestada

Show that potential difference can be described as energy transferred per unit charge between the two points.

Respuesta :

Answer:

The potential difference, ΔV, between two points in the electric field can be described as the potential energy transferred per unit charge, ΔU/q₀ , between the two points

ΔV = ΔU/q₀

Explanation:

The force, F, acting on a test charge, q₀, placed in an electric field E is given as follows;

F = q₀·E

The work the electric field does on the charge, W =dU =  F·ds = q₀·E''·dS

[tex]\Delta U = q_0 \times \int\limits^B_A {E \cdot } \, ds[/tex]

The electric potential difference, ΔV, between two points in the electric which is the change in the energy of the system when a test charge is moved between points in the field is goven as follows;

[tex]\Delta V = \dfrac{\Delta U}{q_0} = -\int\limits^B_A {E \cdot } \, ds[/tex]

Therefore, given that, we have;

[tex]\Delta V = \dfrac{\Delta U}{q_0} = \dfrac{-q_o \times \int\limits^B_A {E \cdot } \, ds}{q_0} = \dfrac{F \cdot ds}{q_0} = \dfrac{W}{q_0}[/tex]

Therefore, the potential energy transferred per unit charge, ΔU/q₀ can be described as the potential difference between two points in the electric field, and vice versa.

A force(F), acting on a charged particle, [tex]q_0[/tex], placed in an electric field E is given by the following:

[tex]\to F = q_0 \times E[/tex]

  • An effect of an electromagnetic current on a charge

         [tex]\to W =dU = F\times ds = q_0 \times E''\times dS\\\\ \to \Delta U= q_0 \times \int^{B}_{A} \ E \cdot ds\\\\[/tex]

  • An electric potential differential, [tex]\Delta V[/tex], across two places inside the electric field, that represents the change in energy of a system when a testing charge is moved between points in the field, is calculated as follows.

            [tex]\to \Delta V =\frac{\Delta U}{q_0} =-\int^{B}_{A} E \cdot ds\\\\[/tex]

  • Therefore, given that, we have;

     [tex]\to \Delta V =\frac{\Delta U}{q_0} = \frac{-q_0 \times \int^{B}_{A} E \cdot ds}{q_0} =\frac{F \cdot ds}{q_0}=\frac{W}{q_0}\\\\[/tex]

  • As a result, the potential energy transmitted per unit charge, [tex]\frac{\Delta U}{q_0}[/tex], may be represented as the potential difference between two places in the electromagnetic current, and vice versa.

So, the final answer is:

  • A potential difference, [tex]\Delta V[/tex], between 2 points in an electric field could be described as the potential power transmitted per unit of charge, [tex]\frac{\Delta U}{q_0}[/tex], between the 2 points.

             [tex]\to \Delta V=\frac{\Delta U}{q_0}[/tex]

Learn more about the potential difference:

brainly.com/question/12198573