Answer: 3.28 s, 14.76 m
Explanation:
Given
Water moves horizontally with a speed of [tex]v=4.5\ m/s[/tex]
It falls from a height of [tex]h=53\ m[/tex]
Time is taken to fall this much height is
[tex]\Rightarrow t=\sqrt{\dfrac{2h}{g}}\quad [\text{As there is no initial vertical velocity}]\\\\\Rightarrow t=\sqrt{\dfrac{2\times 53}{9.8}}\\\\\Rightarrow t=3.28\ s[/tex]
In this time, water moves horizontally by
[tex]\Rightarrow d=4.5\times 3.28\\\Rightarrow d=14.76\ m[/tex]