contestada

Rank the following compounds in order of decreasing boiling point:

a. sodium bromide (NaBr)
b. acetylene (C2H2
c. (CH3I)

Respuesta :

Answer:

Sodium Bromide (NaBr) boiling point > Iodomethane (CH3I) > Acetylene (C2H2) boiling point

Explanation:

Boiling Point of a liquid is the temperature at which, it's vapour pressure  equalises pressure of gas above it.

Sodium Bromide (NaBr) boiling point = 1,396 °C

Acetylene (C2H2) boiling point  = - 84°C

Iodomethane (CH3I) = 42°C

So, in decreasing order :  1396 > 42 > -84

Hence, Sodium Bromide (NaBr) boiling point > Iodomethane (CH3I) > Acetylene (C2H2) boiling point