Answer:
D)15m³
Step-by-step explanation:
the given ratio tells us that the Volume of figure-B is three times as much as the Volume of figure-A
so we acquire:
[tex] \displaystyle A _{ \text{figure - B}} = A _{ \text{figure - A}} \times 3[/tex]
substitute the given volume of the figure-A:
[tex] \displaystyle A _{ \text{figure - B}} =5 {m}^{3} \times 3[/tex]
simplify multiplication:
[tex] \displaystyle A _{ \text{figure - B}} =15 {m}^{3} [/tex]
hence, our answer is D)
