The standard error of the sampling size is 121 is 1.84
"a measure of the statistical accuracy of an estimate, equal to the standard deviation of the theoretical distribution of a large population of such estimates."
"In the standard error formula, the factor sqrt[ (N - n ) / (N - 1) ] is called the finite population correction or fpc. When the population size is very large relative to the sample size, the fpc is approximately equal to one; and the standard error formula can be approximated by:
σx = σ / sqrt(n)."
Given,
Standard deviation of the sample is 20.2
and sample size is = 121
Standard error is = [tex]\sigma/\sqrt(n)[/tex]
i.e. standard error = [tex]20.2/\sqrt(121)[/tex] = 20.2/ 11 = 1.84
Hence, option A is true.
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