How many formula units (particles of AgNO3) are in 5.50 grams of AgNO3?
(picture for answer choices)

Answer:
No of molcules(N)= 1.98×10^22
Explanation:
m=5.5, Mm= 167, NA= 6.02×10^23
Moles(n)= m/M= N/NA
5.5/167 = N/6.02×10^23
SIMPLIFY
N=1.98×10^22molecules