ryleighgreer
contestada

10.0 mL of 3.0 M sulfuric acid has been added to 50.0 mL of water.
What is the new concentration?
M1V1=M2V2
15 M
1.7 M
0.60M
0.20 M

Respuesta :

Answer:

the new concentration is 0.60M

Explanation:

The computation of the new concentration is shown below;

We know that

M1V1=M2V2

(3.0M) (10.0 mL) = M2 (50.0mL)

30 = M2 (50.0mL)

So, M2 = 0.60 M

Hence, the new concentration is 0.60M

The same is considered and relevant

Otras preguntas