Please factor using the x method
( please do not answer if you don't know how to do it )

Answer:
[tex]2(x - 5) ( 9x - 2)[/tex]
Step-by-step explanation:
((2•3^2x^2) - 94x) + 20
Pull like factors :
18x^2 - 94x + 20 = 2 • (9x^2 - 47x + 10)
Factor
9x^2 - 47x + 10
The first term is, 9x^2 its coefficient is 9.
The middle term is, -47x its coefficient is -47.
The last term, "the constant", is +10
Step-1: Multiply the coefficient of the first term by the constant 9 • 10 = 90
Step-2: Find two factors of 90 whose sum equals the coefficient of the middle term, which is -47.
-90 + -1 = -91
-45 + -2 = -47
Step-3: Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -45 and -2
9x^2 - 45x - 2x - 10
Step-4: Add up the first 2 terms, pulling out like factors :
9x • (x-5)
Add up the last 2 terms, pulling out common factors :
2 • (x-5)
Step-5: Add up the four terms of step 4 :
(9x-2) • (x-5)
Which is the desired factorization
thus the answer is
[tex]2(x - 5) ( 9x - 2)[/tex]
Answer:
Solution given:
18x²-94x+20
taking common
2(9x²-47x+10)
doing middle term factorization
90=45*2
2(9x²-45x-2x+10)
2(9x(x-5)-2(x-5))
2(9x-2)(x-5)
2(x-5)(9x-2)
Last one is a required answer.