Answer:
Area of the figure = 25.7 units²
Step-by-step explanation:
Area of the given figure = Area of rectangle ABCD - Area of the semicircle with diameter CD
Area of the rectangle ABCD = Length × Width
= BC × AB
= 8 × 4
= 32 units²
Area of the semicircle = [tex]\frac{1}{2}\pi r^{2}[/tex]
Here, r = radius of the semicircle
r = [tex]\frac{\text{Diameter}}{2}[/tex]
r = [tex]\frac{1}{2}(CD)[/tex]
r = [tex]\frac{4}{2}[/tex]
r = 2 units
Therefore, area of the semicircle = [tex]\frac{1}{2}\pi (2)^2[/tex]
= 2π
= 6.28 units²
Area of the given figure = 32 - 6.28
= 25.72 units²
≈ 25.7 units²
