Answer:
[tex]V_2=10L[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to calculate the required new volume by using the Charles' law as a directly proportional relationship between temperature and volume:
[tex]\frac{V_2}{T_2} =\frac{V_1}{T_1}[/tex]
In such a way, we solve for V2 and plug in V1, T1 and T2 to obtain:
[tex]V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5.0L*600K}{300K}\\\\V_2=10L[/tex]
Regards!
