Answer:
[tex]E=2.15\times 10^{-4}\ J[/tex]
Step-by-step explanation:
Given that,
The capacitance of the capacitor, [tex]C=2.2\times 10^{-6}\ F[/tex]
Voltage of the power supply, V = 14 V
We need to find the energy stored in the capacitor.
The formula for the stored energy in the capacitor is given by :
[tex]E=\dfrac{1}{2}CV^2[/tex]
Put all the values,
[tex]E=\dfrac{1}{2}\times 2.2\times 10^{-6}\times 14^2\\\\E=2.15\times 10^{-4}\ J[/tex]
So, [tex]2.15\times 10^{-4}\ J[/tex] of energy is stored in the capacitor.
