Answer:
The length of the diagonal of the rectangle is of [tex]\sqrt{58}[/tex] units.
Step-by-step explanation:
Pythagorean theorem:
The square of the hypothenuse h is equal to the sum of the squares of sides a and b, that is:
[tex]h^2 = a^2 + b^2[/tex]
Diagonal of a rectangle:
The diagonal is the hypothenuse, while the sides are a and b.
In this question:
The height has coordinates are y = 9 and y = 12, so the height is [tex]a = 12 - 9 = 3[/tex]
The length has coordinates at [tex]x = -6, x = -13[/tex], so the length is [tex]b = -6 - (-13) = 7[/tex]
Diagonal:
[tex]d^2 = a^2 + b^2[/tex]
[tex]d^2 = 3^2 + 7^2[/tex]
[tex]d^2 = 9 + 49[/tex]
[tex]d^2 = 58[/tex]
[tex]d = \sqrt{58}[/tex]
The length of the diagonal of the rectangle is of [tex]\sqrt{58}[/tex] units.
