Answer:
0.373 moles of ammonium carbonate
Explanation:
To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:
(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:
2N = 14.0g/mol*2 = 28.0
8H = 1.0g/mol*8 = 8.0
1C = 12.0g/mol*1 = 12.0
3O = 16.0g/mol*3 = 48.0
Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol
The moles of ammonium carbonate in 35.8g are:
35.8g * (1mol / 96.0g) =
