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Find sin 0, sec 0, and tan 0, where is the angle shown in the figure.
Give exact values, not decimal approximations.

Find sin 0 sec 0 and tan 0 where is the angle shown in the figure Give exact values not decimal approximations class=

Respuesta :

sreedevi102

Answer:

[tex]Let \ base = x\\5^2 = x^2 + 4^2\\25-16 = x^2\\9 = x^2\\x = 3\\\\\\opposite = 4\\adjacent = 3\\hypotenuse = 5\\Sin \theta = \frac{opposite}{hypotenuse} = \frac{4}{5} \\\\Cos\theta = \frac{adjacent}{hypotenuse} =\frac{3}{5}\\\\Tan \theta = \frac{opposite}{adjacent} = \frac{4}{3}[/tex]

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