cynthiaj789 cynthiaj789

25-05-2021
Mathematics

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100 POINTS HELP!
I WILL GIVE BRAINLIEST TO THE BEST ANSWER
FAKE ANSWERS WILL BE REPORTED

100 POINTS HELP I WILL GIVE BRAINLIEST TO THE BEST ANSWER FAKE ANSWERS WILL BE REPORTED class=

Respuesta :

25-05-2021

Answer:

Solution given:

AB parallel BH parallel CH

1.

In triangle ∆AFD ,∆BGD ,∆CHD

<AFD=<BGD=<CHD

[being corresponding angle]

<DAF=<DBG=<DCH

[being corresponding angle]

<D is common for all.

So

∆AFD ~∆BGD ~∆CHD

[By A .A .A. axiom]

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