Answer:
See Explanation
Step-by-step explanation:
The question is incomplete, as the required data to calculate the mean and the median are missing.
To solve this, I will assume the following values:
[tex]13, 18, 13, 14, 13, 16, 14, 21, 13[/tex]
[tex]n = 9[/tex]
The mean is calculated as:
[tex]Mean = \frac{\sum x}{n}[/tex]
[tex]Mean = \frac{13+ 18+ 13+ 14+ 13+ 16+ 14+ 21+ 13}{9}[/tex]
[tex]Mean = \frac{135}{9}[/tex]
[tex]Mean = 15[/tex]
To calculate the median;
Start by sorting the data
[tex]Sorted: 13, 13, 13, 13, 14, 14, 16, 18, 21[/tex]
[tex]n = 9[/tex]
The median is:
[tex]Median = \frac{n + 1}{2}[/tex]
[tex]Median = \frac{9 + 1}{2}[/tex]
[tex]Median = \frac{10}{2}[/tex]
[tex]Median = 5th[/tex]
The median is the 5th item on the list; i.e. 14
So:
[tex]Median = 14[/tex]
The difference (d) between the mean and the median is:
[tex]d = |Mean - Median|[/tex]
[tex]d = |15 -14|[/tex]
[tex]d = |1|[/tex]
Remove absolute bracket
[tex]d=1[/tex]
The difference in the mean and the median of the assumed dataset is 1
