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The propeller in the previous problem slows from 475 rev/min to 187 rev/min in 4.00 s. What is its angular acceleration?

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asuwafohjames

The angular acceleration of the propeller is 7.54 rad/s²

Angular acceleration:

This can be defined as the rate of change of angular velocity. The S.I unit of angular acceleration is rad/s.

The angular acceleration of the propeller can be calculated using the formula below.

⇒ Formular:

  • ∝ = (ω-ω')/t................. Equation 1

⇒ Where:

  • ∝ = angular acceleration of the propeller
  • ω = final angular velocity
  • ω' = initial angular velocity
  • t = time.

From the question,

⇒ Given:

  • ω' = 475 rev/min = (475×0.10472) rad/s = 49.742 rad/s
  • ω = 187 rev/min = (187×0.10472) = 19.583 rad/s
  • t = 4 s

⇒ Substitute these values into equation 1

  • ∝ = (19.583-49.742)/4
  • ∝ = -30.159/4
  • ∝ = -7.54 rad/s².

Note: The negative sign tells that the propeller is slowing down.

Hence, The angular acceleration of the propeller is 7.54 rad/s²

Learn more about angular acceleration here: https://brainly.com/question/20912191

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