a line passes through the point (-10,9) and has a slope of -1/2 write an equation in slope-intercept form for this line.
PLEASE do this fast. I will mark the correct answer brainliest. Also, please only answer with the right answer not stuff unrelated or not answering the question. Please hurry. Thank you so so so much.

Respuesta :

Answer:

[tex]y=-\frac{1}{2} x+4[/tex]

Step-by-step explanation:

The equation of a straight line in slope intercept form is given by:

y = mx + c;

where y, x are variables, m is the slope of the line and c is the y intercept (that is value of y when x is 0).

The equation of a line passing through point ([tex]x_1,y_1[/tex]) with a slope of -1/2 is given by:

[tex]y-y_1=m(x-x_1)[/tex]

Given that the line passes through the point (-10,9) and has a slope of -1/2. Hence the equation of the line is:

[tex]y-9=-\frac{1}{2}(x-(-10)) \\\\y-9=-\frac{1}{2} (x+10)\\\\y=-\frac{1}{2} x-5+9\\\\y=-\frac{1}{2} x+4[/tex]