Answer: There are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.
Explanation:
Given: Mass = 30.0 g
Specific heat = [tex]0.90 J/g^{o}C[/tex]
[tex]T_{1} = 22^{o}C[/tex]
[tex]T_{2} = 80^{o}C[/tex]
Formula used to calculate the heat energy requires is as follows.
[tex]q = m \times C \times (T_{2} - T_{1})[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat capacity of substance
[tex]T_{1}[/tex] = initial temperature
[tex]T_{2}[/tex] = final temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times (T_{2} - T_{1})\\= 30.0 g \times 0.90 J/g^{o}C \times (80 - 22)^{o}C\\= 1566 J[/tex]
Thus, we can conclude that there are 1566 joules of heat needed to raise the temperature of 30.0 g of aluminum from 22°C to 80°C, if the specific heat of aluminum is 0.90 J/g°C.
