Hi there!
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I believe your answer is:
[tex]b=\frac{1}{8}[/tex]
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Here’s why:
To solve the equation shown for 'b', we would have to do inverse operations on both sides to 'undo' values.
[tex]\boxed{\text{Solve for 'B':}}\\\\\frac{3}{8} +\frac{b}{3}=\frac{5}{12}\\\\------\\\rightarrow\frac{3}{8} +\frac{b}{3}=\frac{5}{12}\\\\\rightarrow\frac{3}{8} - \frac{3}{8} +\frac{b}{3}=\frac{5}{12}-\frac{3}{8}\\\\ ------\\\frac{5}{12}-\frac{3}{8}\\\\\text{24 is the LCM of 12 and 8.}\\\\\frac{5}{12}-\frac{3}{8} \rightarrow \frac{10}{24}-\frac{9}{24}\\\\\frac{10}{24}-\frac{9}{24} =\frac{1}{24}\\\\\text{Therefore:}\\\\\boxed{\frac{5}{12}-\frac{3}{8}=\frac{1}{24}}\\\\ ------\\[/tex]
[tex]\rightarrow\frac{b}{3}=\frac{1}{24}\\\\\rightarrow(\frac{b}{3})3*(\frac{1}{24})3\\\\\rightarrow\boxed{b=\frac{3}{24}}\\\\--------\\\boxed{\text{The answer can be simplified.}}\\\\\rightarrow\frac{3}{24}\rightarrow\frac{3/3}{24/3}\rightarrow\frac{1}{8}\\\\--------\\\\\huge\boxed{b=\frac{1}{8}}[/tex]
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Hope this helps you. I apologize if it’s incorrect.
