A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below:

Which of the following could be used to calculate the total volume of grains that can be stored in the silo?

A. π(8.5ft)2(2ft) + one over three π(2ft)2(13ft − 8.5ft)
B. π(2ft)2(8.5ft) + one over three π(2ft)2(13ft − 8.5ft)
C. π(8.5ft)2(2ft) + one over three π(13ft − 8.5ft)2(2ft)
D. π(2ft)2(8.5ft) + one over threeπ(13ft − 8.5ft)2(2ft)

A company that manufactures storage bins for grains made a drawing of a silo The silo has a conical base as shown below Which of the following could be used to class=

Respuesta :

Answer:

B. π(2ft)²(8.5ft) + one over three π(2ft)²(13ft − 8.5ft)

Step-by-step explanation:

total volume =

π.r².h1 + ⅓π.r².h2

= π(2ft)²(8.5ft) + ⅓π(2ft)²(13ft-8.5ft)

Option B is correct. [tex]V_T=\ \pi (2)^2(8.5)+\frac{1}{3} \pi (2)^2(13-8.5)\\[/tex]

The storage bin is constructed using a cylinder and a cone. Hence the total volume of the grain can be calculated using the formula;

[tex]V_T=V_C+V_{co}[/tex]

Vc is the volume of the cylinder

Vco is the volume of the cone.

For the cylinder:

Height of the cylinder hc = 8.5ft

radius rc = 4/2 = 2ft

[tex]V_c=\pi r_c^2h_c\\V_c=\pi(2)^2(8.5)[/tex]

For the cone:

Height of the cone = (13 - 8.5)ft

radius of the cone = radius of the cylinder rco = 2ft

[tex]V_{co}=\frac{1}{3} \pi r_{co}^2h_{co}\\ V_{co}=\frac{1}{3} \pi (2)^2(13-8.5)\\[/tex]

Taking the sum of the volumes;

[tex]V_T=\ \pi (2)^2(8.5)+\frac{1}{3} \pi (2)^2(13-8.5)\\[/tex]

This shows that option B is correct.

Learn more about the volume of composite objects here: https://brainly.com/question/14204462