Answer:
This is the order:
1. 3x
2. 3x + 8
3. x^2
4. x^2 + 6
5. 4^x
6. 4^x + 3
(I numbered them only so it would be easier to refer to them)
Step-by-step explanation:
Why is Equation #2 greater than Equation #1?
This is because the equations are the same, except that the second equation is shifted up by eight units. This means that its value is always going to be eight units greater.
This same reasoning applies to Equations 3&4 and 5&6.
Why is Equation #3 greater than Equation #2?
This is because a certain value multiplied by three (even with eight added) will soon be overtaken by that value squared. For example, let's make x= 5
3(5) + 8 = 23
(5)^2 = 25
As you can see, the equation x^2 is already greater in value than 3x + 8.
Why is Equation #5 greater than Equation #4?
This is because a certain value squared will soon be overtaken by 4 to the power of that value. For example, let's make x= 2
(2)^2 + 6= 10
4^2 = 16
As you can see, the equation 4^x is already greater in value than x^2 + 6.
Hope this helps! :)
