Answer:
The correct answer is "164.06 nm".
Explanation:
Refractive index,
n = 1.75
Wavelength,
λ = 525 nm
Now,
The maximum thickness of the film will be:
⇒ [tex]t=\frac{\lambda}{2n}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{525}{2\times 1.75}[/tex]
⇒ [tex]=\frac{525}{3.5}[/tex]
⇒ [tex]=164.06 \ nm[/tex]