Answer:
Logan can mow 1 lawn per hour more than Brian
Step-by-step explanation:
Given
[tex]Logan: 8\ lawns \to 4\ hours[/tex]
See attachment for Brian's graph
First, calculate Logan's hourly rate
[tex]Rate = \frac{Lawn}{Time}[/tex]
[tex]Rate = \frac{8\ lawns}{4\ hours}[/tex]
Rate = 2 lawns per hour
To calculate Brian's rate, we select 2 points from the linear graph
[tex](x_1,y_1) = (1,1)[/tex]
[tex](x_2,y_2) = (2,2)[/tex]
So, the rate is:
[tex]Rate = \frac{y_2 - y_1}{x_2 - x_1}[/tex]
[tex]Rate = \frac{2 - 1}{2 - 1}[/tex]
[tex]Rate = \frac{1}{1}[/tex]
Rate = 1 lawn per hour
So, we have:
[tex]Logan = 2[/tex]
[tex]Brian = 1[/tex]
Calculate the difference (d)
[tex]d = Logan - Brian[/tex]
[tex]d = 2 - 1[/tex]
[tex]d = 1[/tex]
Logan can mow 1 lawn per hour more than Brian
