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Which constant number would you add to both sides of the equation in order to complete the square for the quadratic function 1 = x2 - 6x?​

Which constant number would you add to both sides of the equation in order to complete the square for the quadratic function 1 x2 6x class=

Respuesta :

mhanifa

Answer:

  • 9

Step-by-step explanation:

Identity of the square of a sum:

  • (a + b)² = a² + 2ab + b²

Applied to given equation:

  • 1 = x² - 6x
  • 1 = x² - 2*x*3
  • 1 + 3² = x² - 2*x*3 + 3²
  • 1 + 9 = (x - 3)²

The added constant is 9

msm555

Answer:

Solution given:

equation is:

1=x²-6x

x²-6x-1=0

comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=-1

now

constant no.[tex] {(\frac{b}{2})}^{2}= {(\frac{-6}{2})}^{2}=\frac{36}{4}=9[/tex]

constant required no is 9.

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