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In a fishing contest, the length of the fish caught ranged from 11.5 inches to 23 inches with a mean length of 16.40 inches and standard deviation of 4.71 inches. Assume there was a normal distribution. What percent of the fish caught would have a length greater than 21.11 inches, one standard deviation above the mean?

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Answer:

15 percent

Step-by-step explanation:

Parrain

Based on the length of the fish and the standard deviation above the mean, the percentage of fish that will have a length of more than 21.11 inches is 15.9%.

What percentage of fish will be longer than 21.11 inches?

Using the z table, we find that the z score probability for a length less than 21.11 inches when there is one standard deviation above the mean is 0.841.

The percentage of fish that are greater than 21.11 inches will therefore be:

= 1 - probability that fish is shorter than 21.11 inches

= 1 - 0.841

= 0.159

= 15.9%

Find out more on standard deviation at https://brainly.com/question/13155674.

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