Respuesta :
Answer:
Mean of 64 and standard error of 0.9.
Step-by-step explanation:
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
Phone bills from the residents of the city have a mean of $64 and a standard deviation of $9. Sample of 10.
By the Central Limit Theorem, the mean is 64 and the standard error is [tex]s = \frac{9}{\sqrt{100}} = \frac{9}{10} = 0.9[/tex]
So mean of 64 and standard error of 0.9.
