Answer: [tex]518.4\ cm^3[/tex]
Step-by-step explanation:
Given
The volume of the small block is [tex]300\ cm^3[/tex]
The ratio of the surface area of small to large block is [tex]25:36[/tex]
Suppose the length of the small and large box is a and b
[tex]\therefore \left(\dfrac{6a^2}{6b^2}\right)=\dfrac{25}{36}\\\\\Rightarrow \left(\dfrac{a}{b}\right)^2=\dfrac{25}{36}\\\\\Rightarrow \left(\dfrac{a}{b}\right)=\dfrac{5}{6}\\\\\therefore \text{Ratio of the volumes of two is }\\\\\Rightarrow \dfrac{a^3}{b^3}=\dfrac{5^3}{6^3}\\\\\Rightarrow \dfrac{V_s}{V_l}=\dfrac{125}{216}\\\\\Rightarrow V_l=300\times \dfrac{216}{125}\\\\\Rightarrow V_l=518.4\ cm^3[/tex]