Answer:
[tex]Pair \ of \ lines \ are \ perpendicular, then \ m_1 \times m_2= -1\\[/tex]
A.
y = 2x - 5
y = 2x + 3
[tex]m_1 = 2, m_2 = 2 \\m_1 \cdot m_2 = 4[/tex]
B.
y = (2/3)x + 1
y = (3/2)x + 1
[tex]m_1 = \frac{2}{3}, m_2= \frac{3}{2} \\\\m_1 \cdot m_2=\frac{2}{3} \times \frac{3}{2} = 1[/tex]
C.
y = 3x + 5
y=(-1/3)x - 8
[tex]m_1 = 3, m_2 = \frac{-1}{3} \\\\m_1 \cdot m_2 = 3 \times\frac{-1}{3} = -1[/tex]
D.
y= 4x - 5
y= -4x + 2
[tex]m_1 = 4, m_2= -4\\\\m_1 \cdot m_2 = -16[/tex]
option C
