Calculate the new temperature when a container of
gas has a pressure of 795 mm Hg at 273 K and the
pressure is lowered to 358 mm Hg.
(Gay Lussac's Law) P1T2/P2T1

- 0.00165
- 246
- 123
- 606

Respuesta :

Answer: The new temperature of container is 123 K.

Explanation:

Given: [tex]P_{1}[/tex] = 795 mm Hg,     [tex]T_{1}[/tex] = 273 K

[tex]P_{2}[/tex] = 358 mm Hg,          [tex]T_{2}[/tex] = ?

Formula used to calculate the new temperature is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{795 mm Hg}{273 K} = \frac{358 mm Hg}{T_{2}}\\T_{2} = 123 K[/tex]

Thus, we can conclude that the new temperature of container is 123 K.