The school cafeteria sells two kinds of wraps: vegetarian and chicken. The vegetarian wrap costs $1.00 and the chicken wrap costs $2.70. Today they made $244.60 from the 146 wraps sold. How many of the wraps sold were vegetarian?

Respuesta :

Answer:

88 Vegetarian Wraps Sold.

Step-by-step explanation:

This is a System of Equations Problem.

Your Two Systems Are:

v(1)+c(2.7)=244.6 and c+v=146

c = chicken wraps and v = vegetarian wraps

Each chicken wrap costs $2.70 (2.7). Put the variable of c next to (2.7) meaning to multiply.

Each vegetarian wrap costs $1 (1). Put the variable of v next to (1)

244.60 (244.6) is the total amount of money made from selling the wraps. This will be the total of the equation.

v(1)+c(2.7)=244.6

Solve 2.7c+v=244.6 for v.

Add -2.7c to both sides.

2.7c+v+−2.7c=244.6+−2.7c

v=−2.7c+244.6

Substitute −2.7c+244.6 for v in c+v=146.

c+v=146

c+−2.7c+244.6=146

Simplify both sides of the equation.

−1.7c+244.6=146

Add -244.6 to both sides.

−1.7c+244.6+−244.6=146+−244.6

−1.7c=−98.6

Divide both sides by -1.7.

[tex]\frac{-1.7c}{-1.7} =\frac{-98.6}{-1.7}[/tex]

c=58

Substitute 58 for c in v=−2.7c+244.6.

v=−2.7c+244.6

v=(−2.7)(58)+244.6

Simplify both sides of the equation.

v=88

Answer:

c=58 and v=88

88 vegetarian wraps were sold.