[tex] \boxed{ \boxed{\huge{ \mathrm{ \underline{ Answer } ✓ }}}}[/tex]
Figure - 1 :
Let the missing side as " n "
[tex] \mathrm{ \triangle DEF \sim \triangle DRQ}[/tex]
Therefore the sides will be proportional,
- [tex] \dfrac{n}{9} = \dfrac{4}{12} [/tex]
- [tex]n = \dfrac{1}{3} \times 9[/tex]
- [tex]n = 3 \: \: units[/tex]
_____________________________
Figure - 2 :
Let the missing side as " m "
The Triangles are similar, therefore their sides will be proportional.
- [tex] \dfrac{m}{8} = \dfrac{9}{6} [/tex]
- [tex]m = \dfrac{3}{2} \times 8[/tex]
- [tex]m = 3 \times 4[/tex]
- [tex]m = 12 \: \: units[/tex]
_____________________________
[tex]\mathrm{ ☠ \: TeeNForeveR \: ☠}[/tex]
