[tex]\huge{ \mathfrak{ \underline{ Answer} \: \: ✓ }}[/tex]
Figure - 1 :
The given triangles are similar, so their corresponding sides will be proportional.
Let the missing side be x
- [tex] \dfrac{45}{3x + 9} = \dfrac{20}{16} [/tex]
- [tex]3x + 9 = 45 \times \dfrac{16}{20} [/tex]
- [tex]3x + 9 = 45 \times \dfrac{4}{5} [/tex]
- [tex]3x + 9 = 9 \times 4[/tex]
- [tex]x = \dfrac{27}{3} [/tex]
- [tex]x = 9 \: \: units[/tex]
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Figure - 2 :
The given figure is a Cylinder :
[tex] \large \boxed{ \mathrm{volume = \pi {r}^{2}h }}[/tex]
- [tex] \dfrac{22}{7} \times 9 \times 9 \times 5[/tex]
- [tex] \dfrac{8910}{7} [/tex]
- [tex]1272.3 \: \: yd {}^{3} [/tex]
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[tex]\mathrm{☠ \: TeeNForeveR \: ☠}[/tex]
