Answer:
1574joules of heat
Explanation:
Q= mc( T2-T1)
=150 * 0.477 *22
=1574 joules
1574.1 Joules heat is needed to raise the temperature of 150 g of manganese by 22°C.
The quantity or amount of heat per unit mass required to raise the temperature of a body by one degree Celsius is known as specific heat. The unit of specific heat are joules or calories per gram per degree Celsius. Specific heat is an intensive property.
Calculate heat to raise temperature
Relationship between temperature and heat is expressed as:
Q = mcΔT
where,
Q is heat energy in Joules (J)
m is mass (in grams)
c is specific heat in J/g°C
ΔT is change in temperature
Now, put the values in above formula, we get that
Q = 150 × 0.477 × 22
Q = 150 × 10.494
Q = 1574.1 Joules
Thus, we can say that 1574.1 Joules is needed to raise the temperature of 150g of manganese by 22°C.
Learn more about the specific heat here: https://brainly.com/question/21406849
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