which features describe the graph of y^2/96^2 - x^2/40^2 = 1? select two options

◽️a focus at (104, 0)
◽️a focus at (0, - 96)
◽️a vertex at (- 40, 0)
◽️a vertex at (0, 96)
◽️the center at (0, 0)

which features describe the graph of y2962 x2402 1 select two options a focus at 104 0 a focus at 0 96 a vertex at 40 0 a vertex at 0 96 the center at 0 0 class=

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Answer: d and e

Step-by-step explanation:

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The option describes graph 4. a vertex at (0, 96), and 5. the center at (0, 0) from the given equation  [tex]\dfrac{y^2}{96^2} - \dfrac{x^2}{40^2} = 1[/tex]

What is a system of equations?

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

The given equation is

[tex]\dfrac{y^2}{96^2} - \dfrac{x^2}{40^2} = 1[/tex]

From the given equation,

a = 40

b = 96

(h,k) = (0,0),

The vertices are at (0,96) and at (0, -96).

The curves open upward and downward.

c² = a² + b²

c² = 40² + 96²

c² = 10816

c = 104

Therefore the foci are at (0, -104) and (0, 104).

Hence, the option describes the graph

4. a vertex at (0, 96) is correct.

5. the center at (0, 0) is correct.

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