Again, suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of 24. You then compute the sample mean x-bar for each sample. From the long list of sample means, you create the sampling distribution of the sample mean, assigning probabilities to all possible values of x-bar. What value should you show at the center of the distribution

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Answer:

Following are the solution to the given question:

Step-by-step explanation:

Please find the complete question in the attached file.

[tex]\bar{x}=650\\\\\sigma =24\\\\n=36\\\\[/tex]

Calculating the sampling distribution of the sample mean:

[tex]\to \mu=\mu_\bar{x}=650[/tex]

Calculating the sampling distribution of the standard deviation:

[tex]\to \sigma_\bar{x}=\frac{\sigma}{\sqrt{n}}=\frac{24}{\sqrt{36}}=\frac{24}{6}=4[/tex]

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