Answer:
[tex]E=4.5*10^-^9J[/tex]
Explanation:
From the question we are told that:
Capacitor [tex]C=1.0nf[/tex]
Induction [tex]I=3.0mH[/tex]
Voltage [tex]V=3.0[/tex]
Generally the equation for Max charge on Capacitor is mathematically given by
[tex]Q_{max}=C*V[/tex]
[tex]Q_{max}=1*10^{-9}*3[/tex]
[tex]Q_{max}=3*10^{-9}C[/tex]
Generally the equation for Energy in magnetic field of the coil is mathematically given by
Since
Energy stored in capacitor = Energy in magnetic field of the coil
Therefore
[tex]E = (1/2)* C * V^2[/tex]
[tex]E= 0.5 * 1*10^{-9} *3^2[/tex]
[tex]E=4.5*10^-^9J[/tex]
