contestada

A chemist must dilute 61.9 mL of 548. nM aqueous sodium carbonate (Na2CO3) solution until the concentration falls to 484. nM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in milliliters. Round your answer to 3 significant digits.

Respuesta :

Cricetus

Answer:

The final volume will be "70.08 mL".

Explanation:

The given values are:

Molar mass,

M1 = 548 nM

or,

     = [tex]5.48\times 10^{-7} \ M[/tex]

M2 = 484 nM

or,

      = [tex]4.84\times 10^{-7} \ M[/tex]  

Volume,

V1 = 61.9 mL

V1 = ?

By using the expression, we get

⇒ [tex]M1\times V1=M2\times V2[/tex]

or,

⇒            [tex]V2=\frac{M1\times V1}{M2}[/tex]

By substituting the values, we get

                    [tex]=\frac{5.48\times 10^{-7}\times 61.9}{4.84\times 10^{-7}}[/tex]

                    [tex]=\frac{339.212}{4.84}[/tex]

                    [tex]=70.08 \ mL[/tex]

Otras preguntas