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A set of charged plates have an
area of 8.22*10^-4 m^2 and
separation 2.42*10^-5 m. The
plates are charged with
5.24*10^-8 C. What is the
potential difference V between
the plates?
(Unit = V)

pls hurry <3

Respuesta :

Answer:

175

Explanation:

its for Acellus

The potential difference is V=1.743*10^-7

The voltage is generally referred to as the electric potential difference and  it can be measured using a voltmeter. The electrical potential difference between the two plates is expressed as q=CV.

CALCULATION

we know,

q=CV

q={EA/d}*V

here q= 5.24*10^-8C

       A=8.22*10^-5m^2

       d=2.42*10^-8m

therefore , C={( 8.85*10^-12)*(8.22*10^-5)}/(2.42*10^-8)

                 C=3.006*10^-1

q=CV

q/C=V

V=1.743*10^-7

refer https://brainly.com/question/26733095

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