The diagonal of the square whose area is 32 square ft.is 8ft.
What is pythagoras theorem?
It says that in a right angled triangle the square of hypotenuse is the sum of the square of the base and the square of height.
How to calculate the length of diagonal?
Let the side of the square be x
So the area becomes [tex]x^{2}[/tex]
[tex]x^{2}[/tex]=32
x=4[tex]\sqrt{2}[/tex] ft.
If we draw a diagonal in a square it forms a triangle in which we can easily apply the pythagoras theorem.
The length of the diagonal becomes
=[tex]\sqrt{(4\sqrt{2}) ^{2}+ (4\sqrt{2}) ^{2} }[/tex]
=[tex]\sqrt{64}[/tex]
=8
Hence the length of the diagonal will be 8 ft.
Learn more about pythagoras theorem at https://brainly.com/question/343682
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