Answer:
The correct solution is "3.6975 M".
Explanation:
The given values are:
Volume of solution,
V = 23.2 mL
Density,
D = 1.42 g/mL
Final volume,
= 200 mL
or,
= 0.2 L
Now,
The mass will be:
= [tex]D\times V[/tex]
= [tex]1.42\times 23.1[/tex]
= [tex]32.802 \ g[/tex]
Mass of HNO₃ will be:
= [tex]\frac{32.802}{0.704}[/tex]
= [tex]46.59375 \ g[/tex]
Mol of HNO₃ will be:
= [tex]\frac{mass}{MW}[/tex]
= [tex]\frac{46.59375}{63}[/tex]
= [tex]0.7395 \ mol[/tex]
hence,
The concentration will be:
= [tex]\frac{mol \ of \ HNO_3}{final \ V}[/tex]
= [tex]\frac{0.7395}{0.2}[/tex]
= [tex]3.6975 \ M[/tex]
