Answer:
She has 9 pounds
Step-by-step explanation:
Given
[tex]Bread = \frac{1}{3}[/tex]
[tex]Granola = \frac{4}{9}[/tex]
[tex]Used = 7[/tex]
Required
The total in her supply
Represent the cranberry with c.
So:
[tex]\frac{1}{3}c + \frac{4}{9}c = 7[/tex] ---- Used cranberry
Take LCM
[tex]\frac{3c + 4c}{9} = 7[/tex]
[tex]\frac{7c}{9} = 7[/tex]
Solve for c
[tex]c= 7 * \frac{9}{7}[/tex]
[tex]c= 9[/tex]