We keep brackets
(4n^2 + 3n - 5 ) - (2n^2 + 3n + 6)
We change signs and we group
4n^2 - 2n^2 + 3n - 3n - 5-6
We simplify
2m^2 - 11
Answer: = 2.n^2 - 11
The value of (4n^2 + 3n - 5) - (2n^2 + 3n+ 6) is 2n^2 - 11
The polynomial expression is given as;
(4n^2 + 3n - 5) - (2n^2 + 3n+ 6)
Open the bracket
4n^2 + 3n - 5 - 2n^2 - 3n- 6
Evaluate the like terms
2n^2 - 11
Hence, the value of (4n^2 + 3n - 5) - (2n^2 + 3n+ 6) is 2n^2 - 11
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