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Answer:
The numbers of ways to permute letters of the word Illinois if the two Ls must be consecutive is 7.
The word ILLINOIS contains 7 letters.
How do you find the number of distinguishable permutations of the letters in a word?
To estimate the number of different permutations, consider the total number of letters factorial and divide by the frequency of each letter factorial. The little n's exist the frequencies of each various (different) letter.
We will use the formula for the number of permutations with imperceptible objects. Since the two L's must be consecutive, we consider them to be a single letter LL. Then the word ILLINOIS contains n = 7 letters: 3 I's, 1 LL, 1 N, 1 O, and 1S.
Hence the number of methods to permute letters of the word ILLINOIS if the two L's must be consecutive exists:
[tex]$\frac{7 !}{3 ! 1 ! 1 ! 1 ! 1 !}=7 \cdot 6 \cdot 5 \cdot 4=840 \text {. }$[/tex]
The word ILLINOIS contains 7 letters.
To learn more about permutations
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