Answer:
4368 ways
Step-by-step explanation:
We want to choose 5 objects,without replacement from 16 distinct objects.
We can use combination in this case. The formula for the combination is given by :
[tex]_{n}C_r=\dfrac{n!}{r!(n-r)!}[/tex]
We have, n = 16 and r = 5
So,
[tex]_{16}C_5=\dfrac{16!}{5!(16-5)!}\\\\_{16}C_5=\dfrac{16!}{5!11!}\\\\=4368[/tex]
So, there are 4368 ways in which we want to choose 5 objects,without replacement from 16 distinct objects.
