Answer:
[tex]h=3.18\times 10^{-9}\ m[/tex]
Explanation:
Given that,
The volume of a drop, [tex]V=10^{-10}\ m^3[/tex]
The radius of the circular film, [tex]r=10^{-1}\ m[/tex]
We need to find the thickness of the film.
We know that,
Volume, [tex]V=\pi r^2 h[/tex]
So,
[tex]h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10^{-10}}{\pi \times (10^{-1})^2}\\\\h=3.18\times 10^{-9}\ m[/tex]
So, the thickness of the file is equal to[tex]3.18\times 10^{-9}\ m[/tex].
