Answer:
The absolute maximum on the interval 0 < x < 3 is at x = 2 and f(2) = 0. Since x = 2 can only give an absolute maximum, so there is no absolute minimum.
Step-by-step explanation:
f(x) = (-x + 2)⁴
to find the absolute maximum and minimum values, we differentiate f(x) with respect to x.
So df(x)/dx = f'(x) = 4(-x + 2)³
The maximum and minimum values are obtained when f'(x) = 0
So, 4(-x + 2)³ = 0
⇒ (-x + 2)³ = 0
⇒ -x + 2 = 0
-x = -2
x = 2
Now, f(2) = (-2 + 2)⁴ = 0⁴ = 0
So, the absolute maximum on the interval 0 < x < 3 is at x = 2 and f(2) = 0. Since x = 2 can only give an absolute maximum, so there is no absolute minimum.
