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A test bar of nonferrous material has a diameter of 0.253 inches. Upon applying a tensile load, the sample exhibited 0.002 plastic strain at 3400 lb and the maximum load during testing was 6200 lb and occurred at an engineering strain of 0.65; and breaking occurred at 4400 lb. The sample diameter at fracture was measured to be 0.15 inches.

Required:
a. The yield strength of the material is :________
b. The UTS of the material is:________

Respuesta :

ogorwyne

Answer:

a. 67607.9psi

b. 123278.33

Explanation:

to get the yield strength of the material

= load/ cross sectional area

cross sectional area = π * 0.253²/4

= 0.0502927

The yield strenght

= 3400/0.0502927

= 67609.9 psi

b. the uts of the material

= maximum load/cross sectional area

= 6200/0.0502927

= 123278.33

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