Respuesta :
Answer:
[tex]{ \tt{n _{w} = \frac{real \: depth}{aparent \: depth} }} \\ \\ \frac{4}{3} = \frac{4}{d} \\ { \tt{d = 3 \: meters}}[/tex]
Answer:
ans: 5.33 or 16/3
Explanation:
refractive index = apparent depth/ real deapth
so
apparent depth = 4×(4/3)