Answer:
0.0597in/s
Step-by-step explanation:
The volume of the spherical balloon V= 4/3πr³
r is the radius of the balloon
The rate at which the volume is changing dV/dt is expressed as;\
dV/dt = dV/dr*dr/dt
dV/dr = 3(4/3πr²)
dV/dr = 4πr²
dV/dr = 4π(2)²
dV/dr = 16π
dV/dt = 3 in³/s
Substitute inti the formula
3 = 16πdr/dt
dr/dt = 3/16π
dr/dt = 3/50.24
dr/dt = 0.0597in/s
Hence the balloon is increasing at the rate of 0.0597in/s
